难度:简单
给你个整数数组 arr
,其中每个元素都 不相同。
请你找到所有具有最小绝对差的元素对,并且按升序的顺序返回。
输入:arr = [4,2,1,3]
输出:[[1,2],[2,3],[3,4]]
输入:arr = [1,3,6,10,15]
输出:[[1,3]]
输入:arr = [3,8,-10,23,19,-4,-14,27]
输出:[[-14,-10],[19,23],[23,27]]
/**
* 排序
* @desc 时间复杂度 O(logN) 空间复杂度 O(logN)
* @param arr
* @returns
*/
export function minimumAbsDifference(arr: number[]): number[][] {
arr.sort((a, b) => a - b)
let minDiff = Number.MAX_VALUE
const ans: number[][] = []
const len = arr.length
for (let i = 0; i < len - 1; i++) {
const diff = arr[i + 1] - arr[i]
if (diff > minDiff) continue
if (diff < minDiff) {
ans.length = 0
minDiff = diff
}
ans.push([arr[i], arr[i + 1]])
}
return ans
}