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$sql ="INSERT INTO test (dbnewsid,dbnewstime,dbnewstitle,dbnewsvalues,dbnewsclass) VALUES ( NULL ,'$_POST[dbnewstime]','$_POST[dbnewstitle]','$_POST[dbnewsvalues]','$_POST[dbnewsclass]')"; //新增資料
mysqli_query($link,$sql)or die ("無法新增".mysql_error()); //執行sql語法