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tutorials-v5/time-evolution/022_v5_paper-smesolve.md

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@@ -5,7 +5,7 @@ jupyter:
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extension: .md
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format_name: markdown
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format_version: '1.3'
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jupytext_version: 1.13.8
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jupytext_version: 1.16.4
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kernelspec:
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display_name: Python 3 (ipykernel)
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language: python
@@ -27,7 +27,7 @@ However, this solver is of course quite general and can thus also be applied to
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In this example we look at an optical cavity whose output is subject to homodyne detection.
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Such a cavity obeys the general stochastic master equation
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$d \rho(t) = -i [H, \rho(t)] dt + \mathcal{D}[a] \rho (t) dt + \mathcal{H}[a] \rho dW(t)$
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$d \rho(t) = -i [H, \rho(t)] dt + \mathcal{D}[a] \rho (t) dt + \mathcal{H}[a] \rho\, dW(t)$
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with the Hamiltonian
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$\mathcal{H}[a]\rho = a \rho + \rho a^\dagger - tr[a \rho + \rho a^\dagger]$
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captures the conditioning of the trajectory through continious monitoring of the operator $a$.
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captures the conditioning of the trajectory through continuous monitoring of the operator $a$.
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The term $dW(t)$ is the increment of a Wiener process that obeys $\mathbb{E}[dW] = 0$ and $\mathbb{E}[dW^2] = dt$.
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Note that a similiar example is available in the [QuTiP user guide](https://qutip.readthedocs.io/en/qutip-5.0.x/guide/dynamics/dynamics-stochastic.html#stochastic-master-equation).
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## Solving for the Time Evolution
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We calculate the predicted trajectory conditioned on the continious monitoring of operator $a$.
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We calculate the predicted trajectory conditioned on the continuous monitoring of the operator $a$.
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This is compared to the regular `mesolve()` solver for the same model but without resolving conditioned trajectories.
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```python
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We plot the averaged homodyne current $J_x = \langle x \rangle + dW / dt$ and the average system behaviour $\langle x \rangle$ for 500 trajectories.
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This is compared with the prediction of the regular `mesolve()` solver that does not include the conditioned trajectories.
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Since the conditioned expectation values do not depend on the trajectories, we expect that this reproduces the result of the standard `me_solve`.
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Since the conditioned expectation values do not depend on the trajectories, we expect that this reproduces the result of the standard `mesolve()`.
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```python
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stoc_meas_mean = np.array(stoc_solution.measurement).mean(axis=0)[0, :].real

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