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cutting_rod.cpp
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89 lines (81 loc) · 1.14 KB
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/**
Programação Dinâmica
Problema Cutting Rod
Rodrigo Paes
*/
#include <bits/stdc++.h>
using namespace std;
#define MAX 10001
int values[MAX];
int memo[MAX];
int naive(int n)
{
if (n == 0)
{
return 0;
}
else
{
int best = INT_MIN;
for (int i = 0; i < n; ++i)
{
best = max(best, values[i] + naive(n-i-1));
}
return best;
}
}
int topdown_dp(int n)
{
if (memo[n] != -1)
{
return memo[n];
}
if (n == 0)
{
memo[n] = 0;
}
else
{
int best = INT_MIN;
for (int i = 0; i < n; ++i)
{
best = max(best, values[i] + topdown_dp(n-i-1));
}
memo[n] = best;
}
return memo[n];
}
int bottomup_dp(int n)
{
int best;
memo[0] = 0;
// j é o tamanho do subproblema
for (int j = 1; j <= n; ++j)
{
best = INT_MIN;
for (int i=0; i < j; ++i)
{
best = max(best, values[i] + memo[j-i-1]);
}
memo[j] = best;
}
return memo[n];
}
int main()
{
int n;
scanf("%d", &n);
while (n)
{
for (int i=0; i < n; ++i)
{
scanf("%d", &values[i]);
}
memset( memo, -1, sizeof memo);
// printf("%d\n", topdown_dp(n));
// printf("%d\n", bottomup_dp(n));
// printf("%d\n", naive(n));
scanf("%d", &n);
}
return 0;
}