1672 - Richest Customer Wealth

1672. Richest Customer Wealth

Problem Statement

You are given an m x n integer grid accounts where accounts[i][j] is the amount of money the i​​​​​​​​​​​th​​​​ customer has in the j​​​​​​​​​​​th​​​​ bank. Return the wealth that the richest customer has.

A customer's wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.

 

Example 1:

Input: accounts = [[1,2,3],[3,2,1]]
Output: 6
Explanation:
1st customer has wealth = 1 + 2 + 3 = 6
2nd customer has wealth = 3 + 2 + 1 = 6
Both customers are considered the richest with a wealth of 6 each, so return 6.

Example 2:

Input: accounts = [[1,5],[7,3],[3,5]]
Output: 10
Explanation:
1st customer has wealth = 6
2nd customer has wealth = 10
3rd customer has wealth = 8
The 2nd customer is the richest with a wealth of 10.```

<p><strong class="example">Example 3:</strong></p>

Input: accounts = [[2,8,7],[7,1,3],[1,9,5]] Output: 17

<p> </p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>m == accounts.length</code></li>
<li><code>n == accounts[i].length</code></li>
<li><code>1 &lt;= m, n &lt;= 50</code></li>
<li><code>1 &lt;= accounts[i][j] &lt;= 100</code></li>
</ul>


<details>
<summary>

#### _Click to open Hints_

</summary>

- Calculate the wealth of each customer
- Find the maximum element in array.

</details>

## Solutions

### [_Rust_](richest_customer_wealth.rs)

```rs [Rust]
impl Solution {
    pub fn maximum_wealth(accounts: Vec<Vec<i32>>) -> i32 {
        let mut max = 0;

        for account in accounts {
            let mut sum = 0;
            for money in account {
                sum += money;
            }
            if sum > max {
                max = sum;
            }
        }
        max
    }
}

...