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| 1 | +use std::collections::HashMap; |
| 2 | + |
| 3 | +struct DictionaryNode { |
| 4 | + value: char, |
| 5 | + items: HashMap<char, DictionaryNode>, |
| 6 | + ends_at: bool, |
| 7 | + word: String, |
| 8 | +} |
| 9 | + |
| 10 | +impl DictionaryNode { |
| 11 | + |
| 12 | + fn new(value: char) -> Self { |
| 13 | + Self { |
| 14 | + value, |
| 15 | + items: HashMap::new(), |
| 16 | + ends_at: false, |
| 17 | + word: String::from(""), |
| 18 | + } |
| 19 | + } |
| 20 | +} |
| 21 | + |
| 22 | +struct Dictionary { |
| 23 | + root: DictionaryNode, |
| 24 | +} |
| 25 | + |
| 26 | +impl Dictionary { |
| 27 | + |
| 28 | + fn new() -> Self { |
| 29 | + Self { |
| 30 | + root: DictionaryNode::new('*') |
| 31 | + } |
| 32 | + } |
| 33 | + |
| 34 | + fn add_word(&mut self, word: String) { |
| 35 | + let mut current = &mut self.root; |
| 36 | + for letter in word.chars() { |
| 37 | + if !current.items.contains_key(&letter) { |
| 38 | + let node = DictionaryNode::new(letter); |
| 39 | + current.items.insert(letter, node); |
| 40 | + } |
| 41 | + current = current.items.get_mut(&letter).unwrap(); |
| 42 | + } |
| 43 | + current.ends_at = true; |
| 44 | + current.word = word; |
| 45 | + } |
| 46 | + |
| 47 | + fn replace_word<'a>(&'a self, word: &'a str) -> &'a str { |
| 48 | + let mut result = word; |
| 49 | + let mut current = &self.root; |
| 50 | + for letter in word.chars() { |
| 51 | + if current.items.contains_key(&letter) { |
| 52 | + current = ¤t.items[&letter]; |
| 53 | + if current.ends_at { |
| 54 | + result = ¤t.word; |
| 55 | + break; |
| 56 | + } |
| 57 | + } else { |
| 58 | + break; |
| 59 | + } |
| 60 | + } |
| 61 | + result |
| 62 | + } |
| 63 | + |
| 64 | +} |
| 65 | + |
| 66 | +/// In English, we have a concept called root, which can be followed by some other word to form |
| 67 | +/// another longer word - let's call this word derivative. For example, when the root `"help"` is |
| 68 | +/// followed by the word `"ful"`, we can form a derivative `"helpful"`. |
| 69 | +/// |
| 70 | +/// Given a `dictionary` consisting of many roots and a `sentence` consisting of words separated by |
| 71 | +/// spaces, replace all the derivatives in the sentence with the root forming it. If a derivative |
| 72 | +/// can be replaced by more than one root, replace it with the root that has the shortest length. |
| 73 | +/// |
| 74 | +/// Return the `sentence` after the replacement. |
| 75 | +struct Solution; |
| 76 | + |
| 77 | +impl Solution { |
| 78 | + |
| 79 | + fn to_dictionary(words: Vec<String>) -> Dictionary { |
| 80 | + let mut result = Dictionary::new(); |
| 81 | + for word in words { |
| 82 | + result.add_word(word); |
| 83 | + } |
| 84 | + result |
| 85 | + } |
| 86 | + |
| 87 | + pub fn replace_words(dictionary: Vec<String>, sentence: String) -> String { |
| 88 | + let dict = Self::to_dictionary(dictionary); |
| 89 | + let result: Vec<&str> = sentence |
| 90 | + .split(' ') |
| 91 | + .map(|word| dict.replace_word(word)) |
| 92 | + .collect(); |
| 93 | + result.join(" ") |
| 94 | + } |
| 95 | + |
| 96 | +} |
| 97 | + |
| 98 | +#[cfg(test)] |
| 99 | +mod tests { |
| 100 | + use super::Solution; |
| 101 | + |
| 102 | + #[test] |
| 103 | + fn example_1() { |
| 104 | + let dictionary = vec![str!("cat"), str!("bat"), str!("rat")]; |
| 105 | + let sentence = str!("the cattle was rattled by the battery"); |
| 106 | + let result = Solution::replace_words(dictionary, sentence); |
| 107 | + assert_eq!(result, "the cat was rat by the bat"); |
| 108 | + } |
| 109 | + |
| 110 | + #[test] |
| 111 | + fn example_2() { |
| 112 | + let dictionary = vec![str!("a"), str!("b"), str!("c")]; |
| 113 | + let sentence = str!("aadsfasf absbs bbab cadsfafs"); |
| 114 | + let result = Solution::replace_words(dictionary, sentence); |
| 115 | + assert_eq!(result, "a a b c"); |
| 116 | + } |
| 117 | + |
| 118 | +} |
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