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| 1 | +/// You are given an integer array `heights` representing the heights of |
| 2 | +/// buildings, some `bricks`, and some `ladders`. |
| 3 | +/// |
| 4 | +/// You start your journey from building `0` and move to the next building by |
| 5 | +/// possibly using bricks or ladders. |
| 6 | +/// |
| 7 | +/// While moving from building `i` to building `i+1` (0-indexed), |
| 8 | +/// |
| 9 | +/// * If the current building's height is greater than or equal to the next |
| 10 | +/// building's height, you do not need a ladder or bricks. |
| 11 | +/// |
| 12 | +/// * If the current building's height is less than the next building's height, |
| 13 | +/// you can either use one ladder or `(h[i+1] - h[i])` bricks. |
| 14 | +/// |
| 15 | +/// Return the furthest building index (0-indexed) you can reach if you use the |
| 16 | +/// given ladders and bricks optimally. |
| 17 | +struct Solution; |
| 18 | + |
| 19 | +impl Solution { |
| 20 | + |
| 21 | + fn prefix_diff(n: usize, heights: &Vec<i32>) -> Vec<i32> { |
| 22 | + let mut result = Vec::new(); |
| 23 | + let mut previous = heights[0]; |
| 24 | + for i in 1..n { |
| 25 | + let current = heights[i]; |
| 26 | + let diff = current - previous; |
| 27 | + if diff > 0 { |
| 28 | + result.push(diff); |
| 29 | + } |
| 30 | + previous = current; |
| 31 | + } |
| 32 | + result |
| 33 | + } |
| 34 | + |
| 35 | + fn bricks_for_buildings(heights: &Vec<i32>, bricks: i32) -> i32 { |
| 36 | + let mut bricks = bricks; |
| 37 | + let mut result = 0; |
| 38 | + |
| 39 | + for height in heights { |
| 40 | + if bricks >= *height { |
| 41 | + bricks -= height; |
| 42 | + result += 1; |
| 43 | + } else { break; } |
| 44 | + } |
| 45 | + |
| 46 | + result |
| 47 | + } |
| 48 | + |
| 49 | + fn check_furthest(n: usize, heights: &Vec<i32>, bricks: i32, ladders: i32) -> bool { |
| 50 | + let mut diffs = Self::prefix_diff(n, heights); |
| 51 | + diffs.sort(); |
| 52 | + let brick_buildings = Self::bricks_for_buildings(&diffs, bricks); |
| 53 | + let total = brick_buildings + ladders; |
| 54 | + total >= diffs.len() as i32 |
| 55 | + } |
| 56 | + |
| 57 | + pub fn furthest_building(heights: Vec<i32>, bricks: i32, ladders: i32) -> i32 { |
| 58 | + let n = heights.len(); |
| 59 | + let result: i32; |
| 60 | + |
| 61 | + if Self::check_furthest(n, &heights, bricks, ladders) { |
| 62 | + result = n as i32; |
| 63 | + } else { |
| 64 | + let mut last_bad = n; |
| 65 | + let mut last_good = 1; |
| 66 | + |
| 67 | + while last_bad - last_good > 1 { |
| 68 | + let mid = last_good + (last_bad - last_good) / 2; |
| 69 | + if Self::check_furthest(mid, &heights, bricks, ladders) { |
| 70 | + last_good = mid; |
| 71 | + } else { |
| 72 | + last_bad = mid; |
| 73 | + } |
| 74 | + } |
| 75 | + result = last_good as i32; |
| 76 | + } |
| 77 | + |
| 78 | + result - 1 |
| 79 | + } |
| 80 | + |
| 81 | +} |
| 82 | + |
| 83 | +#[cfg(test)] |
| 84 | +mod tests { |
| 85 | + use super::Solution; |
| 86 | + |
| 87 | + #[test] |
| 88 | + fn example_1() { |
| 89 | + let heights = vec![4,2,7,6,9,14,12]; |
| 90 | + let bricks = 5; |
| 91 | + let ladders = 1; |
| 92 | + let result = Solution::furthest_building(heights, bricks, ladders); |
| 93 | + assert_eq!(result, 4); |
| 94 | + } |
| 95 | + |
| 96 | + #[test] |
| 97 | + fn example_2() { |
| 98 | + let heights = vec![4,12,2,7,3,18,20,3,19]; |
| 99 | + let bricks = 10; |
| 100 | + let ladders = 2; |
| 101 | + let result = Solution::furthest_building(heights, bricks, ladders); |
| 102 | + assert_eq!(result, 7); |
| 103 | + } |
| 104 | + |
| 105 | + #[test] |
| 106 | + fn example_3() { |
| 107 | + let heights = vec![14,3,19,3]; |
| 108 | + let bricks = 17; |
| 109 | + let ladders = 0; |
| 110 | + let result = Solution::furthest_building(heights, bricks, ladders); |
| 111 | + assert_eq!(result, 3); |
| 112 | + } |
| 113 | + |
| 114 | +} |
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