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| 1 | +// Find the sum of two polynomial numbers. Represent the polynomial using single linked list. |
| 2 | + |
| 3 | +// Input Format : |
| 4 | + |
| 5 | +// First line contains the Degree of the 1st polynomial |
| 6 | + |
| 7 | +// Second line contains the Coefficient of 1st polynomial |
| 8 | + |
| 9 | +// Third line contains the degree of the 2nd polynomial |
| 10 | + |
| 11 | +// Fourth line contains the Coefficient of 2nd polynomial |
| 12 | + |
| 13 | +// Sample Input : |
| 14 | + |
| 15 | +// 3 |
| 16 | + |
| 17 | +// 5 2 0 1 |
| 18 | + |
| 19 | +// 2 |
| 20 | + |
| 21 | +// 4 3 1 |
| 22 | + |
| 23 | +// Sample Output: |
| 24 | + |
| 25 | +// 5x^3 + 6x^2 + 3x^1 + 2 |
| 26 | + |
| 27 | +// Explanation: |
| 28 | + |
| 29 | +// 5x^3 + 2x^2 + 1 + 4x^2 + 3x^1 + 1 = 5x^3 + 6x^2 + 3x^1 + 2 |
| 30 | + |
| 31 | +#include<stdio.h> |
| 32 | +#include<stdlib.h> |
| 33 | +struct node |
| 34 | +{ |
| 35 | + int pow; |
| 36 | + int co; |
| 37 | + struct node *next; |
| 38 | +}; |
| 39 | +typedef struct node node; |
| 40 | +node *position; |
| 41 | +void insert(node *p,int c,int po) |
| 42 | +{ |
| 43 | + node *newnode=malloc(sizeof(node)); |
| 44 | + newnode->next=NULL; |
| 45 | + newnode->pow=po; |
| 46 | + newnode->co=c; |
| 47 | + if(p->next==NULL) |
| 48 | + { |
| 49 | + p->next=newnode; |
| 50 | + position=newnode; |
| 51 | + } |
| 52 | + else |
| 53 | + { |
| 54 | + position->next=newnode; |
| 55 | + position=newnode; |
| 56 | + } |
| 57 | +} |
| 58 | +void display(node *ans) |
| 59 | +{ |
| 60 | + node *position=ans->next; |
| 61 | + while(position!=NULL) |
| 62 | + { |
| 63 | + if(position->co!=0) |
| 64 | + { |
| 65 | + printf("%d",position->co); |
| 66 | + if(position->pow!=0) |
| 67 | + { |
| 68 | + printf("x^%d",position->pow); |
| 69 | + printf("+"); |
| 70 | + } |
| 71 | + } |
| 72 | + position=position->next; |
| 73 | + } |
| 74 | +} |
| 75 | +void add(node *poly1,node *poly2) |
| 76 | +{ |
| 77 | + node *ans=malloc(sizeof(node)); |
| 78 | + ans->next=NULL; |
| 79 | + position=ans; |
| 80 | + node *p1=poly1->next; |
| 81 | + node *p2=poly2->next; |
| 82 | + while(p1!=NULL && p2!=NULL) |
| 83 | + { |
| 84 | + node *newnode=malloc(sizeof(node)); |
| 85 | + newnode->next=NULL; |
| 86 | + if((p1->pow==p2->pow)) |
| 87 | + { |
| 88 | + newnode->co=p1->co + p2->co; |
| 89 | + newnode->pow=p1->pow; |
| 90 | + p1=p1->next; |
| 91 | + p2=p2->next; |
| 92 | + } |
| 93 | + else if ((p1->pow > p2->pow)) |
| 94 | + { |
| 95 | + newnode->co=p1->co; |
| 96 | + newnode->pow=p1->pow; |
| 97 | + p1=p1->next; |
| 98 | + } |
| 99 | + else if((p1->pow < p2->pow)) |
| 100 | + { |
| 101 | + newnode->co=p2->co; |
| 102 | + newnode->pow=p2->pow; |
| 103 | + p2=p2->next; |
| 104 | + } |
| 105 | + position->next=newnode; |
| 106 | + position=newnode; |
| 107 | + } |
| 108 | + while(p1!=NULL || p2!=NULL) |
| 109 | + { |
| 110 | + if(p1==NULL && p2==NULL) |
| 111 | + break; |
| 112 | + else{ |
| 113 | + node *newnode=malloc(sizeof(node)); |
| 114 | + newnode->next=NULL; |
| 115 | + /*if(p1==NULL && p2==NULL) |
| 116 | + { |
| 117 | + newnode->co=p1->co + p2->co; |
| 118 | + newnode->pow=p1->pow; |
| 119 | + position->next=newnode; |
| 120 | + position=newnode; |
| 121 | + break; |
| 122 | + }*/ |
| 123 | + { |
| 124 | + if(p1!=NULL) |
| 125 | + { |
| 126 | + newnode->co=p1->co; |
| 127 | + newnode->pow=p1->pow; |
| 128 | + p1=p1->next; |
| 129 | + } |
| 130 | + if(p2!=NULL) |
| 131 | + { |
| 132 | + newnode->co=p2->co; |
| 133 | + newnode->pow=p2->pow; |
| 134 | + p2=p2->next; |
| 135 | + } |
| 136 | + position->next=newnode; |
| 137 | + position=newnode; |
| 138 | + } |
| 139 | + } |
| 140 | + } |
| 141 | + display(ans); |
| 142 | +} |
| 143 | + |
| 144 | +int main() |
| 145 | +{ |
| 146 | + int n,m; |
| 147 | + node *poly1=malloc(sizeof(node)); |
| 148 | + node *poly2=malloc(sizeof(node)); |
| 149 | + poly1->next=NULL; |
| 150 | + poly2->next=NULL; |
| 151 | + scanf("%d",&n); |
| 152 | + for(int i=0;i<=n;i++) |
| 153 | + { |
| 154 | + scanf("%d",&m); |
| 155 | + insert(poly1,m,n-i); |
| 156 | + } |
| 157 | + scanf("%d",&n); |
| 158 | + for(int i=0;i<=n;i++) |
| 159 | + { |
| 160 | + scanf("%d",&m); |
| 161 | + insert(poly2,m,n-i); |
| 162 | + } |
| 163 | + add(poly1,poly2); |
| 164 | + return 0; |
| 165 | +} |
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