Fix handling of \ as an operator

Author: Jentsch

Diff for: src/typescript/Scala.tmLanguage.ts

@@ -677,11 +677,11 @@ export const scalaTmLanguage: TmLanguage = {
           }
         },
         { // Operators with three or more characters
-          match: `(${opchar}${opchar}${opchar}+)`,
+          match: `(${opchar}|[\\\\]){3,}`,
           name: 'keyword.operator.scala'
         },
         { // Operators with two characters
-          match: `(${opchar}${opchar}|\\\\${opchar})`,
+          match: `((?:${opchar}|[\\\\]){2,})`,
           captures: {
             '1': {
               patterns: [
@@ -702,7 +702,7 @@ export const scalaTmLanguage: TmLanguage = {
           }
         },
         { // Operators with one character
-          match: `(?<!${letter}_)(${opchar})`,
+          match: `(?<!${letter}_)(${opchar}|\\\\)`,
           captures: {
             '1': {
               patterns: [

Diff for: syntaxes/Scala.tmLanguage.json

@@ -0,0 +1,3 @@
+a \\\ b
+
+a \+\ b

Diff for: tests/snap/#191.test.scala

@@ -0,0 +1,10 @@
+>a \\\ b
+#^^ source.scala
+#  ^^^ source.scala keyword.operator.scala
+#     ^^^ source.scala
+>
+>a \+\ b
+#^^ source.scala
+#  ^^^ source.scala keyword.operator.scala
+#     ^^^ source.scala
+>

Diff for: tests/snap/#191.test.scala.snap

@@ -34,3 +34,18 @@
 //   ^^^ keyword.operator.scala
    a &= b
 //   ^^ keyword.operator.scala
+
+   a \ b
+//   ^ keyword.operator.scala
+
+   a \\ b
+//   ^^ keyword.operator.scala
+
+   a \/ b
+//   ^^ keyword.operator.scala
+
+   a /\ b
+//   ^^ keyword.operator.scala
+
+   a \\\ b
+//   ^^^ keyword.operator.scala