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FR: Image orientation #2

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achterbahn opened this issue Oct 7, 2015 · 0 comments

achterbahn commented Oct 7, 2015

Needed to know, if an image is "portrait", "landscape" (or "square"). Added the following to the snippet:

/* Orientation */
$ratio = $attr[0]/$attr[1];
switch ($ratio) {
    case $ratio > 1:
        $orientation = "landscape";
        break;
    case $ratio < 1:
         $orientation = "portrait";
         break;
     case $ratio == 1:
        $orientation = "square";
        break;
 }

and

'orientation' => $orientation,

to the output array.

Hopefully useful for others.

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