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Update Advanced SQL Puzzles Solutions.sql
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Advanced SQL Puzzles/Advanced SQL Puzzles Solutions.sql

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SELECT MIN(StepNumber) AS MinStepNumber,
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MAX(StepNumber) as MaxStepNumber,
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[Status],
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MAX(StepNumber) - MIN(StepNumber) + 1 AS ConsecutiveCount
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COUNT(*) AS ConsecutiveCount,
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MAX(StepNumber) - MIN(StepNumber) + 1 AS ConsecutiveCount_MinMax
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FROM #Groupings2
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GROUP BY Rnk,
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[Status]
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ORDER BY 1, 2;
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/*----------------------------------------------------
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Answer to Puzzle #30
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Select Star

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