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+<h2><a href="https://leetcode.com/problems/regular-expression-matching">10. Regular Expression Matching</a></h2><h3>Hard</h3><hr><p>Given an input string <code>s</code>&nbsp;and a pattern <code>p</code>, implement regular expression matching with support for <code>&#39;.&#39;</code> and <code>&#39;*&#39;</code> where:</p>
+
+<ul>
+	<li><code>&#39;.&#39;</code> Matches any single character.​​​​</li>
+	<li><code>&#39;*&#39;</code> Matches zero or more of the preceding element.</li>
+</ul>
+
+<p>The matching should cover the <strong>entire</strong> input string (not partial).</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> s = &quot;aa&quot;, p = &quot;a&quot;
+<strong>Output:</strong> false
+<strong>Explanation:</strong> &quot;a&quot; does not match the entire string &quot;aa&quot;.
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> s = &quot;aa&quot;, p = &quot;a*&quot;
+<strong>Output:</strong> true
+<strong>Explanation:</strong> &#39;*&#39; means zero or more of the preceding element, &#39;a&#39;. Therefore, by repeating &#39;a&#39; once, it becomes &quot;aa&quot;.
+</pre>
+
+<p><strong class="example">Example 3:</strong></p>
+
+<pre>
+<strong>Input:</strong> s = &quot;ab&quot;, p = &quot;.*&quot;
+<strong>Output:</strong> true
+<strong>Explanation:</strong> &quot;.*&quot; means &quot;zero or more (*) of any character (.)&quot;.
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= s.length&nbsp;&lt;= 20</code></li>
+	<li><code>1 &lt;= p.length&nbsp;&lt;= 20</code></li>
+	<li><code>s</code> contains only lowercase English letters.</li>
+	<li><code>p</code> contains only lowercase English letters, <code>&#39;.&#39;</code>, and&nbsp;<code>&#39;*&#39;</code>.</li>
+	<li>It is guaranteed for each appearance of the character <code>&#39;*&#39;</code>, there will be a previous valid character to match.</li>
+</ul>