Added soundex.py file

Author: wc0development

soundex.py

@@ -0,0 +1,21 @@
+##SOUNDEX ALGORITHM
+
+text = 'AMANMADHUKAR' ##Enter your text here
+plain = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' ## This is the plain text
+code = '01230120022455012623010202' ## Here I have assigned the code value respective to the alphabet 
+l=[] ## Create empty list
+l.append(text[0]) ## So first character goes as it is (here it will be A)
+for i in range(1,len(text)):   ## Traversing from 1st Index i.e. M to R over here that is the last character
+    if(code[plain.index(text[i-1])]!=code[plain.index(text[i])]):  ## Removing Zeroes from the list
+        if (code[plain.index(text[i])] != '0'): ## If not zero
+            l.append(code[plain.index(text[i])]) ## then append into list       
+for i in range(4):  ## Soundex considers only Four characters therefore traversing only four times
+        if (len(l)<4):  ## Suppose the Character less than four then we append 0 in last
+            l.append('0')
+        
+
+print(l) ##printing list
+print(''.join(l[:4])) ##lastly merging the list 
+
+
+## Happy Coding :)