|
| 1 | +""" |
| 2 | +Python version 3.7.0 |
| 3 | +2.2 - Return Kth to Last |
| 4 | +Implement an algorithm to find the kth |
| 5 | +to last element of a singly linked list |
| 6 | +Example: |
| 7 | + input: ll = a -> b -> c -> d -> e -> f |
| 8 | + k = 3 |
| 9 | + output: d because d is 3rd to last |
| 10 | +""" |
| 11 | +import unittest |
| 12 | + |
| 13 | + |
| 14 | +class Node: |
| 15 | + def __init__(self, d: int): |
| 16 | + self.data = d |
| 17 | + self.next = None |
| 18 | + |
| 19 | + def __repr__(self): |
| 20 | + return self.__str__() |
| 21 | + |
| 22 | + def __str__(self): |
| 23 | + return '<Node Value: {}>'.format(self.data) |
| 24 | + |
| 25 | + def __eq__(self, other: object): |
| 26 | + if not isinstance(other, Node): |
| 27 | + return NotImplemented |
| 28 | + return self.data == other.data |
| 29 | + |
| 30 | + |
| 31 | +class LinkedList: |
| 32 | + def __init__(self, *numbers: int): |
| 33 | + self.head = None |
| 34 | + self.tail = None |
| 35 | + for num in numbers: |
| 36 | + self.append_to_tail(num) |
| 37 | + |
| 38 | + def append_to_tail(self, d: int) -> None: |
| 39 | + if self.head is None: |
| 40 | + self.head = Node(d) |
| 41 | + self.tail = self.head |
| 42 | + return |
| 43 | + end = Node(d) |
| 44 | + self.tail.next = end |
| 45 | + self.tail = end |
| 46 | + |
| 47 | + def append_to_head(self, d: int) -> None: |
| 48 | + new_head = Node(d) |
| 49 | + new_head.next = self.head |
| 50 | + self.head = new_head |
| 51 | + |
| 52 | + def __repr__(self): |
| 53 | + return self.__str__() |
| 54 | + |
| 55 | + def __str__(self): |
| 56 | + if self.head is None: |
| 57 | + return '<empty>' |
| 58 | + ll = [] |
| 59 | + n = self.head |
| 60 | + while n.next is not None: |
| 61 | + ll.append('{} -> '.format(n.data)) |
| 62 | + n = n.next |
| 63 | + ll.append(str(n.data)) |
| 64 | + return ''.join(ll) |
| 65 | + |
| 66 | + def __eq__(self, other: object): |
| 67 | + if not isinstance(other, LinkedList): |
| 68 | + return NotImplemented |
| 69 | + a = self.head |
| 70 | + b = other.head |
| 71 | + while a is not None and b is not None: |
| 72 | + if a.data != b.data: |
| 73 | + return False |
| 74 | + # otherwise, advance both pointers |
| 75 | + a = a.next |
| 76 | + b = b.next |
| 77 | + return a is None and b is None |
| 78 | + |
| 79 | + |
| 80 | +def kth_to_last(ll: LinkedList, k: int) -> Node: |
| 81 | + """ |
| 82 | + kth_to_last will return the kth to last node |
| 83 | + from the input linked list. |
| 84 | + Going to reverse the linked list and then |
| 85 | + count k steps. |
| 86 | + Runtime: O(N) |
| 87 | + Space Complexity: O(N) |
| 88 | + :param ll: a linked list |
| 89 | + :param k: an integer where k >= 0 |
| 90 | + :return: |
| 91 | + kth to last Node from the linked list |
| 92 | + or None |
| 93 | + """ |
| 94 | + if k <= 0: |
| 95 | + return None |
| 96 | + # build reversed linked list |
| 97 | + reversed_ll = LinkedList(ll.head.data) |
| 98 | + n = ll.head.next |
| 99 | + while n is not None: |
| 100 | + reversed_ll.append_to_head(n.data) |
| 101 | + n = n.next |
| 102 | + # go k steps |
| 103 | + i = 1 |
| 104 | + n = reversed_ll.head |
| 105 | + while n is not None and i < k: |
| 106 | + n = n.next |
| 107 | + i += 1 |
| 108 | + return n |
| 109 | + |
| 110 | + |
| 111 | +class TestKthToLast(unittest.TestCase): |
| 112 | + |
| 113 | + def setUp(self): |
| 114 | + self.test_cases = [ |
| 115 | + ( |
| 116 | + LinkedList(1, 2, 3, 4, 5, 6), |
| 117 | + 2, |
| 118 | + Node(5) |
| 119 | + ), |
| 120 | + ( |
| 121 | + LinkedList(1, 2, 3, 4, 5, 6), |
| 122 | + 1, |
| 123 | + Node(6) |
| 124 | + ), |
| 125 | + ( |
| 126 | + LinkedList(1, 2, 3, 4, 5, 6), |
| 127 | + 4, |
| 128 | + Node(3) |
| 129 | + ), |
| 130 | + ( |
| 131 | + LinkedList(1, 2, 3, 4, 5, 6), |
| 132 | + 5, |
| 133 | + Node(2) |
| 134 | + ), |
| 135 | + ( |
| 136 | + LinkedList(1, 2, 3, 4, 5, 6), |
| 137 | + 6, |
| 138 | + Node(1) |
| 139 | + ), |
| 140 | + ( |
| 141 | + LinkedList(1, 2, 3, 4, 5, 6), |
| 142 | + 7, |
| 143 | + None |
| 144 | + ), |
| 145 | + ( |
| 146 | + LinkedList(1), |
| 147 | + 1, |
| 148 | + Node(1) |
| 149 | + ), |
| 150 | + ( |
| 151 | + LinkedList(5), |
| 152 | + 0, |
| 153 | + None |
| 154 | + ), |
| 155 | + ] |
| 156 | + |
| 157 | + def test_kth_to_last(self): |
| 158 | + for ll, k, expected in self.test_cases: |
| 159 | + self.assertEqual(kth_to_last(ll, k), expected, msg=(ll, expected)) |
| 160 | + |
| 161 | + |
| 162 | +if __name__ == '__main__': |
| 163 | + unittest.main() |
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