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main.go
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package main
import (
"fmt"
)
// Given a list of non-negative numbers and a target integer k, write a function to check
// if the array has a continuous subarray of size at least 2 that sums up to the multiple
// of k, that is, sums up to n*k where n is also an integer.
//
// Example 1:
// Input: [23, 2, 4, 6, 7], k=6
// Output: True
// Explanation: Because [2, 4] is a continuous subarray of size 2 and sums up to 6.
//
// Example 2:
// Input: [23, 2, 6, 4, 7], k=6
//
// Output: True
// Explanation: Because [23, 2, 6, 4, 7] is an continuous subarray of size 5 and sums up to 42.
//
// Note:
// The length of the array won't exceed 10,000.
// You may assume the sum of all the numbers is in the range of a signed 32-bit integer.
// hash based
// shit: k may be negative?
func checkSubarraySum(nums []int, k int) bool {
var sum int
if k < 0 {
k = -k
}
if k == 1 && len(nums) > 1 {
return true
}
var record = map[int]int{}
for i, n := range nums {
if _, ok := record[sum]; !ok {
record[sum] = i - 1
}
sum += n
// adjacent 0
if n == 0 {
if i != 0 && nums[i-1] == 0 {
return true
}
if i != len(nums)-1 && nums[i+1] == 0 {
return true
}
}
for sum >= k {
if j, ok := record[sum-k]; ok {
//fmt.Println(i, j)
if i-j >= 2 {
return true
}
}
if k == 0 {
break
}
sum -= k
}
}
return false
}
// lots of corner case
// impressive, % not -, and can handle negative condition
func checkSubarraySum2(nums []int, k int) bool {
n := len(nums)
if n == 0 {
return k == 0
}
m := make(map[int]int)
m[0] = -1
sum := 0
for i, v := range nums {
sum = sum + v
r := sum
if k != 0 {
r = r % k
}
//find
if index, ok := m[r]; ok && i-index >= 2 {
return true
}
if _, ok := m[r]; !ok {
m[r] = i
}
}
return false
}
func main() {
//fmt.Println(checkSubarraySum([]int{0, 0}, 0))
//fmt.Println(checkSubarraySum([]int{23, 2, 4, 6, 7}, 7))
//fmt.Println(checkSubarraySum([]int{23, 2, 6, 4, 7}, 6))
//fmt.Println(checkSubarraySum([]int{23}, 23))
//fmt.Println(checkSubarraySum([]int{2, 3, 1}, 2))
//fmt.Println(checkSubarraySum([]int{2, 1, 3}, 3))
//fmt.Println(checkSubarraySum([]int{2, 3}, 5))
fmt.Println(checkSubarraySum2([]int{2, 3, 3, 4, 5, 0, 0, 1, 1, 3, 4, 5, 6}, -800))
//
//// -6
//fmt.Println(checkSubarraySum([]int{23, 2, 4, 6, 7}, -6))
//fmt.Println(checkSubarraySum2([]int{0}, 0))
//fmt.Println(checkSubarraySum2([]int{0, 0}, -1))
//fmt.Println(checkSubarraySum2([]int{1, 1000000000}, 1))
fmt.Println(5 / -3, 5 % -3)
}