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unique parallel #38

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CJ-Wright opened this issue Aug 19, 2019 · 0 comments

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CJ-Wright commented Aug 19, 2019

This could work? We might need to scatter the list to the executor first?

def f(x, l):
    xr = x.result()
    for y in l:
        if xr == y.result():
            return "~~NULL_COMPUTE~~"
    return xr

def update(x, who=None):
    future = self.executor.submit(f, x, self.list)
    self.list.append(x)
    yield self._emit(future)

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