From b40eaab3520de5adae9d65938bdee8e7685bcd94 Mon Sep 17 00:00:00 2001
From: Rohit Barua <83600150+Rohit-beep-droid@users.noreply.github.com>
Date: Fri, 7 May 2021 15:04:59 -0400
Subject: [PATCH] Update 100+ Python challenging programming exercises.txt

Added a question and solution for a program called lastoccurrence(). Bit more difficult for beginners, however, it is doable. This should not be much of a challenge for experienced programmers.
---
 ...thon challenging programming exercises.txt | 30 +++++++++++++++++++
 1 file changed, 30 insertions(+)

diff --git a/100+ Python challenging programming exercises.txt b/100+ Python challenging programming exercises.txt
index 97af5aaf..2c4ac5df 100644
--- a/100+ Python challenging programming exercises.txt	
+++ b/100+ Python challenging programming exercises.txt	
@@ -2371,5 +2371,35 @@ solutions=solve(numheads,numlegs)
 print solutions
 
 #----------------------------------------#
+Level 2:
+Slightly difficult for beginners but doable,
+however, should be relatively easy for 
+experienced programmers.
 
+Question:
+Write a program that iterates through a 2D matrix
+and return the last occurrence location of a integer.
+
+Example 1:
+[[3,2,3],[0,5,3],[9,1,7]] --> Return the last occurrence of the integer 3.
+The program should return (1,2).
+
+Example 2:
+[[3,2,3],[0,5,3],[9,1,7]] --> Return the last occurrence of the integer 1.
+The program should return (2,1).
+
+Example 3:
+[[3,2,3],[0,5,3],[9,1,7],[2,0,2]] --> Return the last occurrence of the integer 2.
+The program should return (3,2).
 
+Hints:
+Use range(), len(), and mutiple loops to traverse
+the mutiple lists within the list.
+
+Solution:
+def lastoccurrence(numlist, num):
+    for i in range(len(numlist)-1,-1,-1):
+        for j in range(len(numlist[i])-1,-1,-1):
+	    if numlist[i][j] == num:
+	        return i,j
+#----------------------------------------#