Further modifications

exercise/tex/exercise07.tex

@@ -150,7 +150,7 @@
             i^{(\mathrm{h})}_\mathrm{2}(t_1) = i^{(\mathrm{h})}_\mathrm{2}(t_0) + \Delta i^{(\mathrm{h})}_\mathrm{2} = -44.4 + 75.5 \approx \SI{31}{\ampere}.
             \label{7.1.2:eq:approx_i_2_harm_t1}         
         \end{equation}
-        The preceding steps $\Delta i^{(\mathrm{h})}_\mathrm{2}$ in the trajectory of $i^{(\mathrm{h})}_\mathrm{2}(t)$ can be calculated in the same way
+        The next steps $\Delta i^{(\mathrm{h})}_\mathrm{2}$ in the trajectory of $i^{(\mathrm{h})}_\mathrm{2}(t)$ can be calculated in the same way
         using the corresponding 'number of squares'.  
 \end{solutionblock}
 \input{fig/ex07/Fig_subtask1.3.tex}