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Update tic-tac-toe.py #145

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Update tic-tac-toe.py #145

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11 changes: 8 additions & 3 deletions Python/Python_Games/tic-tac-toe.py
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Original file line number Diff line number Diff line change
Expand Up @@ -5,11 +5,16 @@

# In[5]:

print("---------------------------------------")
print("Welcome to tic tac toe")
print("---------------------------------------")
name1=input("Player 1 name:")
name2=input("Player 2 name:")

from tkinter import *
import tkinter.messagebox
tk = Tk()
tk.title("Tic Tac Toe")
tk.title("Tic Tac Toe game")

pa = StringVar()
playerb = StringVar()
Expand Down Expand Up @@ -54,7 +59,7 @@ def btnClick(bs):
checkForWin()
flag += 1
else:
tkinter.messagebox.showinfo("Tic-Tac-Toe", "Button already Clicked!")
tkinter.messagebox.showinfo("Tic-Tac-Toe", "Button has been already Clicked!")

def checkForWin():
if (b1['text'] == 'X' and b2['text'] == 'X' and b3['text'] == 'X' or
Expand All @@ -70,7 +75,7 @@ def checkForWin():
tkinter.messagebox.showinfo("Tic-Tac-Toe", pa)

elif(flag == 8):
tkinter.messagebox.showinfo("Tic-Tac-Toe", "It is a Tie")
tkinter.messagebox.showinfo("Tic-Tac-Toe", "No winner, there is a tie")

elif (b1['text'] == 'O' and b2['text'] == 'O' and b3['text'] == 'O' or
b4['text'] == 'O' and b5['text'] == 'O' and b6['text'] == 'O' or
Expand Down