[Java] Challenge 0 to 10 (Unreviewed) #379
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| if (openers.contains(c)) { | ||
| stack.push(c); | ||
| } | ||
| if (closers.contains(c)) { |
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good catch thanks!
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| boolean[] b = new boolean[128]; | ||
| for (int i = 0; i < s.length(); i++) { | ||
| b[s.charAt(i)] = true; |
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Does this handle the same character being in an input string twice or more?
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Yes it does. eg. String s = "apple"; String t = "plepva"; output is v found at index: 4 the reason being every character, if found, is stored in its char value index in a boolean array. regardless of how many are present in the string, it will will see true for that char and know that it was present in the original string.
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Still figuring out the right way to branch etc. any feedback is welcome