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Update 58. 打家劫舍.md
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58. 打家劫舍.md

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@@ -6,7 +6,7 @@ class Solution:
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n = len(nums)
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if n<3:
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return max(nums)
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#dp[i]表示截止至第i间房子所能偷窃到的最大金额
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dp = [0]*n
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dp[0] = nums[0]
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dp[1] = max(nums[:2])

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