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{ | ||
"version": 2.0, | ||
"questions": [ | ||
{ | ||
"question": "This is a Sample Question 1?", | ||
"answers": { | ||
"a": "answer1", | ||
"b": "answer2", | ||
"c": "answer3", | ||
"d": "answer4" | ||
}, | ||
"explanations": { | ||
"a": "Explanation 1 <a href='www.google.com'>here</a>", | ||
"b": "Explanation 2", | ||
"c": "Explanation 2", | ||
"d": "Explanation 2" | ||
}, | ||
"correctAnswer": "a", | ||
"difficulty": "beginner" | ||
}, | ||
{ | ||
"question": "This is a Sample Question 2?", | ||
"answers": { | ||
"a": "answer1", | ||
"b": "answer2", | ||
"c": "answer3", | ||
"d": "answer4" | ||
}, | ||
"explanations": { | ||
"a": "Explanation 1 <a href='www.google.com'>here</a>", | ||
"b": "Explanation 2", | ||
"c": "Explanation 2", | ||
"d": "Explanation 2" | ||
}, | ||
"correctAnswer": "c", | ||
"difficulty": "beginner" | ||
} | ||
] | ||
} | ||
{ | ||
"version": 2.0, | ||
"questions": [ | ||
{ | ||
"question": "A signal has a mean of 5 and a variance that fluctuates over time. Can this signal be considered wide-sense stationary (WSS)?", | ||
"answers": { | ||
"a": "Yes, if the autocorrelation depends only on the time difference.", | ||
"b": "No, because the variance is not constant.", | ||
"c": "Yes, if the mean and variance are time-invariant on average.", | ||
"d": "No, because WSS requires both mean and variance to be constant." | ||
}, | ||
"explanations": { | ||
"a": "WSS also requires constant mean and variance.", | ||
"b": "Variance fluctuations violate WSS conditions.", | ||
"c": "Time-invariance on average is not sufficient for WSS.", | ||
"d": "WSS requires both mean and variance to remain constant over time." | ||
}, | ||
"correctAnswer": "b", | ||
"difficulty": "hard" | ||
}, | ||
{ | ||
"question": "An LTI system has an impulse response that is zero for all values of time greater than a certain constant. What does this imply about the system?", | ||
"answers": { | ||
"a": "The system is time-invariant but not necessarily causal.", | ||
"b": "The system is causal and has finite memory.", | ||
"c": "The system is unstable.", | ||
"d": "The system is invertible." | ||
}, | ||
"explanations": { | ||
"a": "Time-invariance does not depend on the impulse response being finite.", | ||
"b": "Finite impulse response implies causality and finite memory.", | ||
"c": "Stability is determined by bounded input and output, not impulse response length.", | ||
"d": "Invertibility is unrelated to finite impulse response." | ||
}, | ||
"correctAnswer": "b", | ||
"difficulty": "hard" | ||
}, | ||
{ | ||
"question": "What does it mean if the transfer function of a system has poles outside the unit circle in the z-domain?", | ||
"answers": { | ||
"a": "The system is unstable.", | ||
"b": "The system is non-causal.", | ||
"c": "The system is time-variant.", | ||
"d": "The system is wide-sense stationary." | ||
}, | ||
"explanations": { | ||
"a": "Poles outside the unit circle indicate instability.", | ||
"b": "Causality is unrelated to pole location.", | ||
"c": "Time-variance is unrelated to pole location.", | ||
"d": "Stability, not WSS, is determined by pole location." | ||
}, | ||
"correctAnswer": "a", | ||
"difficulty": "hard" | ||
}, | ||
{ | ||
"question": "How does the inclusion of a moving average (MA) term in an ARMA model affect its frequency response?", | ||
"answers": { | ||
"a": "It sharpens the peak of the response.", | ||
"b": "It smoothens the response by adding zeros.", | ||
"c": "It introduces poles into the system.", | ||
"d": "It does not affect the frequency response." | ||
}, | ||
"explanations": { | ||
"a": "MA terms generally smoothen the response, not sharpen it.", | ||
"b": "MA terms add zeros, smoothening the overall response.", | ||
"c": "Poles are introduced by the AR term, not the MA term.", | ||
"d": "MA terms significantly affect the frequency response." | ||
}, | ||
"correctAnswer": "b", | ||
"difficulty": "hard" | ||
}, | ||
{ | ||
"question": "What is the key difference between a WSS process and a strict-sense stationary (SSS) process?", | ||
"answers": { | ||
"a": "WSS assumes higher-order moments are time-invariant.", | ||
"b": "SSS requires constant mean and variance, while WSS does not.", | ||
"c": "SSS requires invariance of all moments, while WSS considers only second-order moments.", | ||
"d": "There is no difference; they are equivalent." | ||
}, | ||
"explanations": { | ||
"a": "Higher-order moments are not considered in WSS.", | ||
"b": "WSS also requires constant mean and variance.", | ||
"c": "SSS is stricter, requiring invariance of all moments.", | ||
"d": "WSS and SSS are not equivalent." | ||
}, | ||
"correctAnswer": "c", | ||
"difficulty": "hard" | ||
}, | ||
{ | ||
"question": "If a WSS signal passes through an LTI system, what will be the nature of the output signal?", | ||
"answers": { | ||
"a": "The output signal will always be wide-sense stationary.", | ||
"b": "The output signal will be non-stationary.", | ||
"c": "The output signal will have the same autocorrelation as the input.", | ||
"d": "The output signal will be stationary only if the system is causal." | ||
}, | ||
"explanations": { | ||
"a": "An LTI system preserves WSS properties.", | ||
"b": "Non-stationarity does not result from LTI systems.", | ||
"c": "The autocorrelation of the output depends on the system's impulse response.", | ||
"d": "Causality is unrelated to preserving stationarity." | ||
}, | ||
"correctAnswer": "a", | ||
"difficulty": "hard" | ||
}, | ||
{ | ||
"question": "In an ARMA(1,1) model, what happens when the pole and zero are very close to each other in the z-domain?", | ||
"answers": { | ||
"a": "The system exhibits oscillatory behavior.", | ||
"b": "The system becomes unstable.", | ||
"c": "The system's response becomes heavily damped.", | ||
"d": "The pole-zero cancellation occurs, simplifying the system." | ||
}, | ||
"explanations": { | ||
"a": "Oscillatory behavior depends on pole location, not proximity to zeros.", | ||
"b": "Instability is not caused by pole-zero proximity.", | ||
"c": "Close pole-zero pairs dampen the response.", | ||
"d": "Pole-zero cancellation can simplify the system." | ||
}, | ||
"correctAnswer": "d", | ||
"difficulty": "hard" | ||
}, | ||
{ | ||
"question": "If an AR(2) process has roots that lie on the unit circle, what can be said about the process?", | ||
"answers": { | ||
"a": "The process is stable and stationary.", | ||
"b": "The process is marginally stable but not stationary.", | ||
"c": "The process is unstable and stationary.", | ||
"d": "The process is neither stable nor stationary." | ||
}, | ||
"explanations": { | ||
"a": "Roots on the unit circle indicate marginal stability, not full stability.", | ||
"b": "Marginal stability occurs with roots on the unit circle, but stationarity is lost.", | ||
"c": "Instability is not associated with unit-circle roots.", | ||
"d": "Marginal stability applies here, not full instability." | ||
}, | ||
"correctAnswer": "b", | ||
"difficulty": "hard" | ||
}, | ||
{ | ||
"question": "How does the inclusion of a high-order AR term in an ARMA model influence its autocorrelation properties?", | ||
"answers": { | ||
"a": "It shortens the decay rate of the autocorrelation.", | ||
"b": "It extends the memory of the process.", | ||
"c": "It eliminates oscillatory behavior in the autocorrelation.", | ||
"d": "It has no effect on the autocorrelation." | ||
}, | ||
"explanations": { | ||
"a": "Higher-order AR terms extend the memory, not shorten it.", | ||
"b": "Higher-order AR terms increase the decay length of autocorrelation.", | ||
"c": "Oscillatory behavior depends on pole locations, not order.", | ||
"d": "Autocorrelation is directly influenced by AR terms." | ||
}, | ||
"correctAnswer": "b", | ||
"difficulty": "hard" | ||
}, | ||
{ | ||
"question": "What is the effect of adding a long-memory MA term to an ARMA model in the frequency domain?", | ||
"answers": { | ||
"a": "It increases the bandwidth of the process.", | ||
"b": "It adds sharp resonances at specific frequencies.", | ||
"c": "It suppresses high-frequency components.", | ||
"d": "It enhances low-frequency components." | ||
}, | ||
"explanations": { | ||
"a": "Bandwidth is not directly affected by MA terms.", | ||
"b": "Resonances are typically introduced by poles, not zeros.", | ||
"c": "Long-memory MA terms smoothen or suppress high frequencies.", | ||
"d": "Low-frequency enhancement depends on specific placements of zeros." | ||
}, | ||
"correctAnswer": "c", | ||
"difficulty": "hard" | ||
} | ||
] | ||
} | ||
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